Math Problem Statement
write in c language
Solution
Here is a C program that calculates and displays the average power, average magnitude, and zero crossings from an array of speech data, similar to what you provided in the image.
c#include <stdio.h> #include <math.h> #define ROWS 6 #define COLS 5 // Sample speech data double speechData[ROWS][COLS] = { {0.000000, -0.023438, 0.046875, 0.023438, -0.070313}, {-0.023438, 0.000000, 0.101563, 0.000000, -0.070313}, {-0.031250, 0.023438, 0.117188, -0.031250, -0.062500}, {-0.031250, 0.070313, 0.101563, -0.039063, -0.046875}, {-0.039063, -0.039063, 0.070313, -0.070313, -0.039063}, {-0.039063, -0.039063, 0.054688, -0.070313, -0.031250} }; // Function to calculate average power double calculateAveragePower() { double sumPower = 0.0; int count = 0; for (int i = 0; i < ROWS; i++) { for (int j = 0; j < COLS; j++) { sumPower += speechData[i][j] * speechData[i][j]; count++; } } return sumPower / count; } // Function to calculate average magnitude double calculateAverageMagnitude() { double sumMagnitude = 0.0; int count = 0; for (int i = 0; i < ROWS; i++) { for (int j = 0; j < COLS; j++) { sumMagnitude += fabs(speechData[i][j]); count++; } } return sumMagnitude / count; } // Function to calculate zero crossings int calculateZeroCrossings() { int zeroCrossings = 0; for (int i = 0; i < ROWS; i++) { for (int j = 1; j < COLS; j++) { if ((speechData[i][j - 1] < 0 && speechData[i][j] > 0) || (speechData[i][j - 1] > 0 && speechData[i][j] < 0)) { zeroCrossings++; } } } return zeroCrossings; } int main() { double avgPower = calculateAveragePower(); double avgMagnitude = calculateAverageMagnitude(); int zeroCrossings = calculateZeroCrossings(); printf("SPEECH STATISTICS:\n"); printf("Average Power: %f\n", avgPower); printf("Average Magnitude: %f\n", avgMagnitude); printf("Zero Crossings: %d\n", zeroCrossings); return 0; }
Explanation of Key Parts:
- Speech Data Array: The
speechData
array stores the values from the image. It is a 2D array ofdouble
values. - Average Power Calculation: The
calculateAveragePower
function computes the average power by squaring each value inspeechData
, summing these squares, and dividing by the total count of values. - Average Magnitude Calculation: The
calculateAverageMagnitude
function computes the average magnitude by taking the absolute value of each element, summing them, and dividing by the total count. - Zero Crossings Calculation: The
calculateZeroCrossings
function counts the zero crossings, which occur when consecutive values change sign.
Running the Code
To run this code, compile it with gcc
:
bashgcc -o speech_analysis speech_analysis.c -lm ./speech_analysis
Would you like further details on any part of this code?
Related Questions:
- How would this code handle different data sizes or arrays?
- Can we add a feature to identify the maximum amplitude in the speech data?
- How can this code be modified to calculate root mean square (RMS) instead of average power?
- How can we dynamically input data from a file instead of using a hardcoded array?
- What are the implications of using floating-point precision in C for such calculations?
Tip:
Use the fabs
function from the math library for absolute values to ensure accuracy in magnitude calculations.
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Math Problem Analysis
Mathematical Concepts
Signal Processing
Statistics
Zero Crossing Detection
Formulas
Average Power = (1/N) * Σ(signal[i]^2)
Average Magnitude = (1/N) * Σ(|signal[i]|)
Theorems
-
Suitable Grade Level
Undergraduate
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