Math Problem Statement

Suppose that x units of a product cost C dollars to manufacture and earn revenue of R dollars. The value of x at which the expressions for C and R are equal is the​ break-even quantity, or the number of units that produce 0 profit. Complete parts​ (a) and​ (b)

below.

Cequals=7373xplus+660660​;

Requals=9595x

No more than

2828

units can be sold.

Question content area bottom

Part 1

​(a) Find the​ break-even quantity.

enter your response here

units

​(Simplify your​ answer.)

Solution

To find the break-even quantity, we need to determine the value of xx at which the cost CC equals the revenue RR.

The given equations are: C=73x+660C = 73x + 660 R=95xR = 95x

Step 1: Set CC equal to RR

73x+660=95x73x + 660 = 95x

Step 2: Solve for xx

Rearrange the equation to isolate xx: 660=95x73x660 = 95x - 73x 660=22x660 = 22x

Divide both sides by 22: x=66022x = \frac{660}{22} x=30x = 30

Step 3: Verify the solution

Substitute x=30x = 30 into the original equations for CC and RR:

  • C=73(30)+660=2190+660=2850C = 73(30) + 660 = 2190 + 660 = 2850
  • R=95(30)=2850R = 95(30) = 2850

Since C=RC = R, the solution is correct.

Final Answer:

The break-even quantity is 30 units.

Would you like me to analyze further or help with part (b)? Here are some related questions:

  1. What is the profit when selling 28 units?
  2. How is the break-even point affected if the fixed cost changes?
  3. What happens if the revenue per unit increases to 100?
  4. Can the break-even quantity ever exceed the maximum units that can be sold?
  5. How do you graphically represent the break-even analysis?

Tip: Break-even analysis is crucial for understanding how costs, revenue, and sales volume interact in business.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Break-even Analysis
Basic Algebra

Formulas

C = 73x + 660
R = 95x

Theorems

Equality of linear equations

Suitable Grade Level

Grades 8-10