Math Problem Statement
solve the box plot sum of 60,65,78,85,92,103,120
Solution
To solve a box plot, we need to determine the five-number summary of the given data. This consists of:
- Minimum: The smallest value.
- Q1 (First Quartile): The median of the lower half of the data (excluding the overall median).
- Median: The middle value of the dataset.
- Q3 (Third Quartile): The median of the upper half of the data (excluding the overall median).
- Maximum: The largest value.
Let’s start by arranging the data in ascending order:
Step 1: Identify the Median
Since there are 7 data points (an odd number), the median is the middle value.
Step 2: Calculate Q1 (First Quartile)
Q1 is the median of the lower half: . Since this subset has 3 numbers, the middle value is:
Step 3: Calculate Q3 (Third Quartile)
Q3 is the median of the upper half: . Similarly, the middle value is:
Step 4: Identify the Minimum and Maximum
- Minimum = 60
- Maximum = 120
Five-Number Summary:
- Minimum = 60
- Q1 = 65
- Median = 85
- Q3 = 103
- Maximum = 120
Box Plot Interpretation:
- The box spans from Q1 (65) to Q3 (103).
- The line inside the box is the median (85).
- Whiskers extend from the minimum (60) to the maximum (120).
Would you like more details or have any questions about how I derived these values?
Here are 5 follow-up questions for practice:
- What is the interquartile range (IQR) for this dataset?
- How would you identify outliers based on the IQR method?
- How does the box plot visually represent the spread of the data?
- What does it mean if the median is closer to Q1 or Q3 in a box plot?
- How can we modify the dataset to create a symmetric box plot?
Tip: The interquartile range (IQR) helps identify the spread of the middle 50% of the data, making it a useful measure for detecting outliers!
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Math Problem Analysis
Mathematical Concepts
Box Plot
Five-Number Summary
Quartiles
Formulas
Five-number summary: Min, Q1, Median, Q3, Max
Theorems
Quartile Theorem
Median Calculation
Suitable Grade Level
Grades 6-8
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