Math Problem Statement

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Solution

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Boundedness Theorem

  • Statement:
    If fn:ERf_n : E \to \mathbb{R} is bounded on EE for every nNn \in \mathbb{N}, and fnff_n \to f uniformly on EE, then f:ERf : E \to \mathbb{R} is also bounded on EE.

Example

  • Sequence of Functions:
    fn(x)=nnx+1f_n(x) = \frac{n}{nx + 1} for x(0,1)x \in (0, 1).

  • Observation:

    • Each fnf_n is bounded on (0,1)(0, 1).
    • Pointwise Limit: f(x)=1xf(x) = \frac{1}{x}, which is not bounded on (0,1)(0, 1).
    • Conclusion: The sequence fnf_n cannot converge uniformly on (0,1)(0, 1).

Would you like more details or examples? Here are related questions you can explore:

  1. What is the difference between pointwise and uniform convergence?
  2. How can we formally prove the boundedness theorem?
  3. Why is the function f(x)=1xf(x) = \frac{1}{x} unbounded on (0,1)(0, 1)?
  4. What are other examples where pointwise limits fail to be bounded?
  5. How does the boundedness property relate to practical problems in analysis?

Tip: Uniform convergence ensures the limit function inherits properties like boundedness and continuity—pointwise convergence alone does not guarantee this!

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Math Problem Analysis

Mathematical Concepts

Uniform Convergence
Boundedness of Functions
Pointwise Convergence

Formulas

f_n(x) = n / (nx + 1)
f(x) = 1 / x

Theorems

Boundedness Theorem

Suitable Grade Level

Undergraduate Mathematics