Math Problem Statement
Solution
Let's analyze the statements one by one to determine which are correct.
1. is bounded on .
- The function is unbounded as , since . However, as , remains finite. Therefore, is unbounded from below but bounded from above on .
- This statement is incorrect.
2. is bounded on .
- This function is a Gaussian (normal distribution) function. It is always non-negative and tends to 0 as or . The maximum value is , occurring at .
- This function is indeed bounded for all real numbers.
- This statement is correct.
3. is unbounded on .
- The sine function oscillates between and . On the interval , only takes values between and , so it is bounded.
- This statement is incorrect.
4. is bounded from below on .
- The function tends to as . However, it decreases as increases and is bounded from below by .
- This statement is incorrect because it is not bounded from below (it becomes arbitrarily large as approaches 0).
5. is bounded from above on .
- We have already established that tends to as , but it is bounded from above since is finite.
- This statement is correct.
Correct answers:
- Statement 2: is bounded on .
- Statement 5: is bounded from above on .
Do you want more details on any of the explanations?
Here are 5 related questions:
- What is the behavior of the logarithmic function near zero?
- How do we determine if a function is bounded?
- What are the properties of Gaussian functions like ?
- Can a function be unbounded in one direction but bounded in another?
- How does the sine function behave on different intervals?
Tip: When checking if a function is bounded, always analyze its limits at the boundaries of the given domain.
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Math Problem Analysis
Mathematical Concepts
Logarithmic functions
Gaussian function
Sine function
Reciprocal function
Formulas
y = ln x
y = (1 / √2π) * exp(-x^2 / 2)
y = sin x
y = 1 / x
Theorems
Logarithmic function unbounded behavior as x → 0
Properties of Gaussian function
Sine function boundedness
Reciprocal function properties
Suitable Grade Level
Grades 10-12
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