Math Problem Statement

Выберите все верные утверждения о поведении функций, таких как ln x, sin x, и другие, на различных интервалах.

Solution

Let's analyze the statements one by one to determine which are correct.

1. y=lnxy = \ln x is bounded on (0;10)(0; 10).

  • The function lnx\ln x is unbounded as x0+x \to 0^+, since lnx\ln x \to -\infty. However, as x10x \to 10, lnx\ln x remains finite. Therefore, lnx\ln x is unbounded from below but bounded from above on (0,10)(0, 10).
  • This statement is incorrect.

2. y=12πex2/2y = \frac{1}{\sqrt{2\pi}} e^{-x^2 / 2} is bounded on (;+)(-\infty; +\infty).

  • This function is a Gaussian (normal distribution) function. It is always non-negative and tends to 0 as xx \to \infty or xx \to -\infty. The maximum value is 12π\frac{1}{\sqrt{2\pi}}, occurring at x=0x = 0.
  • This function is indeed bounded for all real numbers.
  • This statement is correct.

3. y=sinxy = \sin x is unbounded on (0;π)(0; \pi).

  • The sine function oscillates between 1-1 and 11. On the interval (0;π)(0; \pi), sinx\sin x only takes values between 00 and 11, so it is bounded.
  • This statement is incorrect.

4. y=1xy = \frac{1}{x} is bounded from below on (0;10)(0; 10).

  • The function 1x\frac{1}{x} tends to ++\infty as x0+x \to 0^+. However, it decreases as xx increases and is bounded from below by 110\frac{1}{10}.
  • This statement is incorrect because it is not bounded from below (it becomes arbitrarily large as xx approaches 0).

5. y=lnxy = \ln x is bounded from above on (0;10)(0; 10).

  • We have already established that lnx\ln x tends to -\infty as x0+x \to 0^+, but it is bounded from above since ln10\ln 10 is finite.
  • This statement is correct.

Correct answers:

  • Statement 2: y=12πex2/2y = \frac{1}{\sqrt{2\pi}} e^{-x^2 / 2} is bounded on (;+)(-\infty; +\infty).
  • Statement 5: y=lnxy = \ln x is bounded from above on (0;10)(0; 10).

Do you want more details on any of the explanations?


Here are 5 related questions:

  1. What is the behavior of the logarithmic function near zero?
  2. How do we determine if a function is bounded?
  3. What are the properties of Gaussian functions like 12πex2/2\frac{1}{\sqrt{2\pi}} e^{-x^2 / 2}?
  4. Can a function be unbounded in one direction but bounded in another?
  5. How does the sine function behave on different intervals?

Tip: When checking if a function is bounded, always analyze its limits at the boundaries of the given domain.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Logarithmic functions
Gaussian function
Sine function
Reciprocal function

Formulas

y = ln x
y = (1 / √2π) * exp(-x^2 / 2)
y = sin x
y = 1 / x

Theorems

Logarithmic function unbounded behavior as x → 0
Properties of Gaussian function
Sine function boundedness
Reciprocal function properties

Suitable Grade Level

Grades 10-12