Math Problem Statement
Based on a survey,
3838%
of likely voters would be willing to vote by internet instead of the in-person traditional method of voting. For each of the following, assume that
1414
likely voters are randomly selected. Complete parts (a) through (c) below.
Question content area bottom
Part 1
a. What is the probability that exactly
1111
of those selected would do internet voting?
In a binomial probability distribution, probabilities can be calculated by using technology, a table of binomial probabilities, or the binomial probability formula, shown below where n is the number of trials, x is the number of successes among n trials, p is the probability of success in any one trial, and q is the probability of failure in any one trial
(qequals=1minus−p).
P(x)equals=StartFraction n exclamation mark Over left parenthesis n minus x right parenthesis exclamation mark x exclamation mark EndFraction times p Superscript x Baseline times left parenthesis 1 minus p right parenthesis Superscript n minus xn!(n−x)!x!•px•(1−p)n−x,
for
xequals=0,
1, 2, ..., n
While either technology or the binomial probability formula can be used to find the simple binomial probabilities, for this exercise, use technology.
Part 2
First find the values of n, x, and p.
nequals=1414
Part 3
xequals=1111
Part 4
pequals=0.380.38
(Type an integer or a decimal. Do not round.)
Part 5
Use these values to calculate
P(1111).
P(1111)equals=0.002070.00207
(Round to five decimal places as needed.)
Part 6
b. If
1111
of the selected voters would do internet voting, is
1111
significantly high? Why or why not?
Having x successes among n trials is a significantly high number of successes if the probability of x or more successes is 0.05 or less. That is, x is a significantly high number of successes if P(x or
more)less than or equals≤0.05.
Part 7
Use technology to calculate
P(1111
or more).
P(1111
or more) = 0.002420.00242
(Round to five decimal places as needed.)
Part 8
Is this probability less than or equal to 0.05?
Yes
Your answer is correct.
No
Part 9
Use this information to determine whether
1111
voters willing to vote by internet is significantly high.
Part 10
c. Find the probability that at least one of the selected likely voters would do internet voting.
Use technology to calculate P(1 or more).
P(1 or more) = enter your response here
(Round to three decimal places as needed.)
Solution
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Binomial Probability
Probability Theory
Significance Testing
Formulas
P(x) = (n! / (n - x)! x!) * p^x * (1 - p)^(n - x)
P(at least 1) = 1 - P(0)
Theorems
Binomial Distribution
Significance Testing (P-value < 0.05)
Suitable Grade Level
College Level or Advanced High School (Grades 11-12)
Related Recommendation
Binomial Probability: Exact Internet Voting Preference for 11 Out of 14 Voters
Binomial Probability: Finding the Probability of 11 Internet Voters out of 14 Likely Voters
Binomial Probability: Internet Voting Likelihood for 12 Out of 15 Voters
Binomial Distribution: Probability of Voters Supporting Federal Involvement in Local Crime
Binomial Probability for Internet Voting with 13 Voters and 34% Probability