Math Problem Statement

In a certain college, 1/3 of the physics majors belong to ethnic minorities. If 10 students are selected at random from the physics majors, what is the probability that exactly 2 belong to an ethnic minority?

Solution

The problem is asking to find the probability that exactly 2 out of 10 randomly selected physics majors belong to an ethnic minority, given that 13\frac{1}{3} of the physics majors are from an ethnic minority.

This is a binomial probability problem where:

  • The total number of trials (students selected) n=10n = 10,
  • The probability of success (selecting a student from an ethnic minority) p=13p = \frac{1}{3},
  • The number of successes (students from ethnic minorities) k=2k = 2.

The binomial probability formula is:

P(X=k)=(nk)pk(1p)nkP(X = k) = \binom{n}{k} p^k (1 - p)^{n - k}

Where:

  • (nk)\binom{n}{k} is the binomial coefficient n!k!(nk)!\frac{n!}{k!(n-k)!},
  • pp is the probability of success,
  • 1p1 - p is the probability of failure,
  • kk is the number of successes (2 in this case),
  • nn is the number of trials (10 here).

Step-by-Step Solution:

  1. Binomial coefficient (102)\binom{10}{2}:

(102)=10!2!(102)!=10×92×1=45\binom{10}{2} = \frac{10!}{2!(10-2)!} = \frac{10 \times 9}{2 \times 1} = 45

  1. Substitute values into the binomial formula:

P(X=2)=45(13)2(23)8P(X = 2) = 45 \left(\frac{1}{3}\right)^2 \left(\frac{2}{3}\right)^8

  1. Simplify:

P(X=2)=45×19×(23)8P(X = 2) = 45 \times \frac{1}{9} \times \left(\frac{2}{3}\right)^8 =45×19×2566561= 45 \times \frac{1}{9} \times \frac{256}{6561} =45×25659049= 45 \times \frac{256}{59049} =1152059049= \frac{11520}{59049} 0.195\approx 0.195

So, the probability that exactly 2 out of the 10 students belong to an ethnic minority is approximately 0.195, or 19.5%.


Would you like more details or have any questions?

Here are five related questions:

  1. How is the binomial distribution used in real-world applications?
  2. What is the expected value in a binomial distribution, and how is it calculated?
  3. How does the probability change if the number of selected students increases?
  4. Can this problem be solved using a normal approximation to the binomial distribution?
  5. How does the variance of a binomial distribution depend on the parameters nn and pp?

Tip: The binomial distribution is ideal for problems involving repeated independent trials with two possible outcomes, like success or failure.

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Math Problem Analysis

Mathematical Concepts

Probability
Binomial Distribution

Formulas

P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
Binomial coefficient: (n choose k) = n! / (k!(n-k)!)

Theorems

Binomial Theorem

Suitable Grade Level

Grades 10-12