Math Problem Statement

Not all visitors to a certain company's website are customers or potential customers. In fact, the company's executives estimate that about 8% of all visitors to the website are looking for other websites. Assume that this estimate is correct and that a random sample of 40 visitors to the website is taken. (a) Estimate the number of visitors in the sample who actually are looking for the company's website by giving the mean of the relevant distribution (that is, the expectation of the relevant random variable). Do not round your response. (b) Quantify the uncertainty of your estimate by giving the standard deviation of the distribution. Round your response to at least three decimal places.

Solution

Let's break down the problem you shared:

Given:

  • 8% of visitors to the website are looking for the company’s website (i.e., potential or actual customers).
  • A random sample of 40 visitors is taken from the total visitors.
  • We are tasked to estimate the following:

(a) The expected number of visitors in the sample who are looking for the company’s website.

The number of visitors who are looking for the company’s website follows a binomial distribution because:

  • There are a fixed number of trials (40 visitors).
  • Each visitor is either looking for the company’s website or not.
  • The probability of success (visitor looking for the company’s website) is 8%, or 0.08.

The expectation E(X)E(X) for a binomial distribution XBinomial(n,p)X \sim \text{Binomial}(n, p) is given by:

E(X)=n×pE(X) = n \times p

where:

  • n=40n = 40 (the number of visitors sampled),
  • p=0.08p = 0.08 (the probability of a visitor being a customer).

E(X)=40×0.08=3.2E(X) = 40 \times 0.08 = 3.2

So, the expected number of visitors in the sample looking for the company’s website is 3.2.

(b) The standard deviation of the distribution.

The standard deviation σ\sigma of a binomial distribution is given by the formula:

σ=n×p×(1p)\sigma = \sqrt{n \times p \times (1 - p)}

Substituting the values:

σ=40×0.08×(10.08)=40×0.08×0.92\sigma = \sqrt{40 \times 0.08 \times (1 - 0.08)} = \sqrt{40 \times 0.08 \times 0.92}

σ=2.9441.715\sigma = \sqrt{2.944} \approx 1.715

Thus, the standard deviation is approximately 1.715 (rounded to three decimal places).


Would you like more details or have any questions?

Here are 5 related questions to expand on this problem:

  1. What is the probability of exactly 4 visitors in the sample being actual customers?
  2. How would the expected value change if the probability of being a customer increased to 10%?
  3. What would the variance be for this distribution?
  4. How does increasing the sample size affect the standard deviation of the estimate?
  5. How would you calculate the probability that fewer than 2 visitors are customers in the sample?

Tip: In binomial problems, the standard deviation depends not only on the probability but also heavily on the sample size. Increasing the sample size typically reduces uncertainty.

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Math Problem Analysis

Mathematical Concepts

Probability
Statistics
Binomial Distribution
Expectation
Standard Deviation

Formulas

E(X) = n × p
σ = √(n × p × (1 - p))

Theorems

Binomial Distribution Properties

Suitable Grade Level

College Level or Advanced High School (Grades 11-12)