## Math Problem Statement

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 17 couples. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 17 births. The value of the mean is = 8.5 . (Type an integer or a decimal. Do not round.) The value of the standard deviation is o = 2.1 . (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of girls or fewer are significantly low. (Round to one decimal place as needed.)

## Solution

## Ask a new question for Free

### By Image

Drop file here or Click Here to upload

## Math Problem Analysis

### Mathematical Concepts

Statistics

Binomial Distribution

Range Rule of Thumb

### Formulas

Mean of Binomial Distribution: μ = n * p

Standard Deviation of Binomial Distribution: σ = √(n * p * (1 - p))

Range Rule of Thumb: Significantly low = μ - 2σ, Significantly high = μ + 2σ

### Theorems

Binomial Distribution Theorem

### Suitable Grade Level

Grades 10-12

## Related Recommendation

Calculate Mean and Standard Deviation for a Binomial Distribution with 24 Trials and p = 0.5

Calculating Mean, Standard Deviation, and Probabilities from a Probability Distribution

Range Rule of Thumb: Significance of 1 Girl in 10 Births

Calculating Mean and Standard Deviation for Peas with Green Pods Using Binomial Distribution

Binomial Distribution: Finding Mean, Standard Deviation, and Usual Values