Math Problem Statement

Two friends bought two bicycles whose prices were in the ratio of 1:5. If they sold them at a loss of 10%, the difference of the money earned by them was Rs. 3600. What was the cost of the costlier cycle?

Question 20Answer

a. 

4000

b. 

5000

c. 

7000

d. 

None

Solution

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Math Problem Analysis

Mathematical Concepts

Ratios
Percentage Loss
Linear Equations

Formulas

Selling Price = Cost Price - Loss
Loss = (Loss Percentage × Cost Price)
Ratio: If prices are in ratio 1:5, then Cost of cheaper bicycle = x, Cost of costlier bicycle = 5x

Theorems

Basic properties of linear equations
Ratio and Proportion theorem

Suitable Grade Level

Grades 8-10