Math Problem Statement
Solution
To determine the best measure of center and measure of variation for this data, consider the data distribution shown in the dot plot.
Observations:
- The data is right-skewed due to a few high outliers in the 90s and 100s.
- In skewed distributions, the median is a better measure of center because it is not affected by outliers.
- For variation, the Interquartile Range (IQR) is preferred in skewed data because it focuses on the middle 50% of the data, minimizing the effect of outliers.
Correct Answer:
D) Median and IQR
Would you like more details on why outliers affect the mean and standard deviation more than the median and IQR?
Related Questions:
- What is the difference between MAD (Mean Absolute Deviation) and IQR in measuring variability?
- How do outliers affect the mean compared to the median?
- Can you explain when it is appropriate to use the mean and standard deviation instead of the median and IQR?
- How do you calculate the IQR from raw data?
- What other statistical measures are sensitive to outliers?
Tip:
When data is symmetrical and without outliers, use the mean and standard deviation. For skewed data or data with outliers, choose the median and IQR.
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Math Problem Analysis
Mathematical Concepts
Measures of central tendency
Measures of variation
Data distribution analysis
Formulas
Median formula
Interquartile Range (IQR) calculation
Theorems
Skewness effect on statistical measures
Suitable Grade Level
Grades 6-8
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