Math Problem Statement

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Find the best fit of the form p(x) = ax + bx^2 to the data (x, y) = (0,0), (1,5), (2,1).

Solution

To find the best-fit curve of the form p(x)=ax+bx2p(x) = ax + bx^2 for the data points provided, we can use the least squares method to determine the values of aa and bb.

The data points given are: (0,0),(1,5),(2,1)(0, 0), (1, 5), (2, 1)

Step 1: Set Up the Equations Using Least Squares

We need to find values of aa and bb that minimize the sum of the squared residuals: (yi(axi+bxi2))2\sum (y_i - (ax_i + bx_i^2))^2

This can be expanded to a system of equations based on each data point. Specifically, we substitute each (xi,yi)(x_i, y_i) into y=ax+bx2y = ax + bx^2 and create a system of equations.

For our three points:

  1. When x=0x = 0 and y=0y = 0: 0=a0+b020=00 = a \cdot 0 + b \cdot 0^2 \Rightarrow 0 = 0

  2. When x=1x = 1 and y=5y = 5: 5=a1+b125=a+b5 = a \cdot 1 + b \cdot 1^2 \Rightarrow 5 = a + b

  3. When x=2x = 2 and y=1y = 1: 1=a2+b221=2a+4b1 = a \cdot 2 + b \cdot 2^2 \Rightarrow 1 = 2a + 4b

Thus, we get the following system of linear equations:

5 = a + b \\ 1 = 2a + 4b \end{cases}$$ ### Step 2: Solve the System of Equations We can solve this system by substitution or elimination. 1. From the first equation: $$a = 5 - b$$ 2. Substitute $$a = 5 - b$$ into the second equation: $$1 = 2(5 - b) + 4b$$ $$1 = 10 - 2b + 4b$$ $$1 = 10 + 2b$$ $$2b = 1 - 10 = -9$$

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Math Problem Analysis

Mathematical Concepts

Least Squares Method
Quadratic Functions
Linear Systems of Equations

Formulas

p(x) = ax + bx^2
Sum of squared residuals

Theorems

Least Squares Approximation

Suitable Grade Level

Undergraduate Level