This image appears to show a beam supported by a roller at one point and a pin or fixed support at another. There are two types of loads acting on the beam:

1. Distributed Load (w = 200 lb/ft) applied over the left section of the beam, spanning 6 feet.
2. Point Load (1,500 lb) located 8 feet from the roller support, 2 feet from the pin support on the right side.

Let’s analyze the system to find the reactions at the supports. Here's a step-by-step outline of how to approach the problem:

Step 1: Define the system and label points

• Left end: Pin Support (A)
• Roller support: 6 feet from the pin support (B)
• Distributed load: $w = 200 \, \text{lb/ft}$ applied over 6 feet.
• Point load: $1500 \, \text{lb}$ applied 8 feet from B.

Step 2: Replace the distributed load with a concentrated load

The total load from the distributed load is: $w_{\text{total}} = 200 \, \text{lb/ft} \times 6 \, \text{ft} = 1200 \, \text{lb}$ This load acts at the centroid of the distributed load, which is 3 feet from point B.

Step 3: Apply equilibrium equations

We can solve this statically indeterminate problem by summing forces and moments to determine the reaction forces at A and B.

• $\sum F_y = 0$ (vertical forces equilibrium)
• $\sum M_A = 0$ (moments about point A)

I can calculate the reactions based on this. Would you like me to proceed with the calculations?