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This image appears to show a beam supported by a roller at one point and a pin or fixed support at another. There are two types of loads acting on the beam:

1. **Distributed Load (w = 200 lb/ft)** applied over the left section of the beam, spanning 6 feet.
2. **Point Load (1,500 lb)** located 8 feet from the roller support, 2 feet from the pin support on the right side.

Let’s analyze the system to find the reactions at the supports. Here's a step-by-step outline of how to approach the problem:

### Step 1: Define the system and label points
- Left end: Pin Support (A)
- Roller support: 6 feet from the pin support (B)
- Distributed load: \( w = 200 \, \text{lb/ft} \) applied over 6 feet.
- Point load: \( 1500 \, \text{lb} \) applied 8 feet from B.

### Step 2: Replace the distributed load with a concentrated load
The total load from the distributed load is:
\[
w_{\text{total}} = 200 \, \text{lb/ft} \times 6 \, \text{ft} = 1200 \, \text{lb}
\]
This load acts at the centroid of the distributed load, which is 3 feet from point B.

### Step 3: Apply equilibrium equations
We can solve this statically indeterminate problem by summing forces and moments to determine the reaction forces at A and B.

- \(\sum F_y = 0\) (vertical forces equilibrium)
- \(\sum M_A = 0\) (moments about point A)

I can calculate the reactions based on this. Would you like me to proceed with the calculations?

Determine the reactions at the supports for a beam subjected to a distributed load (200 lb/ft over 6 ft) and a point load (1,500 lb) located 8 ft from the roller support.

Analyze the reactions of a beam subjected to a 200 lb/ft distributed load over 6 feet and a 1,500 lb point load. The beam is supported by a roller and a pin. Learn how to use equilibrium equations to calculate support reactions.

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