Math Problem Statement
Solution
The image shows a beam with a uniform distributed load of over a span of 6 feet and a concentrated point load of located 8 feet from the left end of the beam. The beam is supported by a roller support at the 6 ft mark and a pin support at the far right end (10 ft from the roller support).
Step-by-step analysis:
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Distributed Load (w = 200 lb/ft over 6 feet): The total distributed load can be calculated as: This distributed load acts at the center of the 6 ft span, which is 3 ft from the left end.
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Concentrated Load: The concentrated load is 1,500 lb located at 8 ft from the left end.
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Supports: There are two supports: a roller support at 6 ft (from the left) and a pin support at 16 ft (from the left).
Equilibrium Equations:
The system must satisfy the conditions of static equilibrium:
- Sum of vertical forces:
- Sum of moments about a point (usually one of the supports):
Would you like to proceed with solving for the support reactions and further analysis (e.g., shear force, bending moment diagrams)?
Here are five questions to expand on the topic:
- How do we calculate the location of the resultant force of a distributed load?
- What is the difference between a pin support and a roller support in beam analysis?
- How do we determine the moment caused by a distributed load on a beam?
- What are the common methods for analyzing statically determinate beams?
- How does the position of the loads on the beam affect the support reactions?
Tip:
In beam analysis, always start by calculating the reactions at the supports before proceeding to analyze internal shear forces and bending moments.
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Math Problem Analysis
Mathematical Concepts
Statics
Equilibrium of Forces
Beam Loading
Support Reactions
Shear Force and Bending Moment
Formulas
ΣF_y = 0 (Sum of vertical forces)
ΣM = 0 (Sum of moments)
Distributed Load Total = w × length
Moment of a force = Force × Distance
Theorems
Principle of Static Equilibrium
Moment Equilibrium Theorem
Suitable Grade Level
Undergraduate - Civil/Mechanical Engineering
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