Math Problem Statement
A steel pipe having a length of 1 m, an outside diameter of 0.2 m, and a wall thickness of 10 mm, is subjected to an axial compression of 200 kN. Assuming a modulus of elasticity of 200 GPa and a Poisson’s ratio of 0.3, find a. the shortening of the pipe, b. the increase in the outside diameter, and c. the increase in the wall thickness.
Solution
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Math Problem Analysis
Mathematical Concepts
Mechanics of Materials
Stress and Strain
Elasticity
Poisson’s Ratio
Axial Compression
Formulas
Axial stress formula: σ = P / A
Axial strain: ε = σ / E
Change in length: ΔL = ε * L
Radial strain: εr = -ν * ε
Change in diameter: ΔD_o = εr * D_o
Change in wall thickness: Δt = εr * t
Theorems
Hooke's Law
Poisson’s Effect
Suitable Grade Level
Undergraduate Engineering (Year 1-2)
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