The question asks to find the average speed of an object between 11:00 and 12:00 based on the graph provided.

To calculate the average speed, we use the formula:

$\text{Average Speed} = \frac{\text{Change in Distance}}{\text{Change in Time}}$

Step 1: Identify the change in distance (Δd)

• At 11:00, the distance is approximately 30 km (based on the graph at the start of section B).
• At 12:00, the distance is approximately 50 km (based on the graph at the end of section C).

$\Delta d = 50 \, \text{km} - 30 \, \text{km} = 20 \, \text{km}$

Step 2: Identify the change in time (Δt)

• The time interval is from 11:00 to 12:00, which is a 1-hour interval.

$\Delta t = 1 \, \text{hour}$

Step 3: Calculate the average speed

$\text{Average Speed} = \frac{20 \, \text{km}}{1 \, \text{hour}} = 20 \, \text{km/h}$

However, the provided options do not include 20 km/h. Since this discrepancy exists, it is likely due to a misreading of the intervals or the choices not matching up exactly with the graphical readings.

Would you like a more detailed explanation or clarification on how to interpret the graph? Let me know if you need more assistance.

Here are 5 related questions:

1. How do you find the average speed if the graph is nonlinear?
2. What is the difference between instantaneous speed and average speed?
3. How can you determine the total distance traveled using a graph?
4. What are the implications of zero slope segments in distance-time graphs?
5. How can the unit of speed change depending on the units used for time and distance?

Tip: Always carefully check the axis and scale of the graph when interpreting values!