To determine whether the driver broke the speed limit, we first need to calculate the average speed over the distance between the two toll booths.

Step 1: Calculate Time Taken

The two photographs provide timestamps:

• Time at the first toll booth: 4:00 PM
• Time at the second toll booth: 4:20 PM

The time difference between 4:00 PM and 4:20 PM is: $\text{Time Taken} = 20 \text{ minutes} = \frac{20}{60} \text{ hours} = \frac{1}{3} \text{ hours}$

Step 2: Calculate Average Speed

The driver traveled 21 miles in $\frac{1}{3}$ hours. To find the average speed, we use the formula: $\text{Average Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{21 \text{ miles}}{\frac{1}{3} \text{ hours}} = 21 \times 3 = 63 \text{ miles per hour}$

Step 3: Compare with the Speed Limit

The speed limit is 55 miles per hour. The calculated average speed is 63 miles per hour.

Conclusion:

Since the driver's average speed is 63 miles per hour, which exceeds the speed limit of 55 miles per hour, the photo evidence suggests that the driver was speeding during the time between the two toll booths.

Would you like further details or have any questions?

Here are 5 related questions for further exploration:

1. How could the driver argue that the speed was not consistently over the limit?
2. What assumptions are made in using average speed to prove speeding?
3. What would the average speed be if the time was 25 minutes instead of 20 minutes?
4. Can you calculate the speed if the driver had traveled 30 miles in 40 minutes?
5. How does instantaneous speed differ from average speed in this context?

Tip: Always check if the time or distance data involves rounding, as it can affect the accuracy of calculations.