Math Problem Statement

Given the function f(x) = -x^2 - 8x + 21, determine the average rate of change of the function over the interval -10 ≤ x ≤ 0.

Solution

We are tasked with finding the average rate of change of the function f(x)=x28x+21f(x) = -x^2 - 8x + 21 over the interval [10,0][-10, 0].

The average rate of change of a function over an interval [a,b][a, b] is given by the formula:

Average rate of change=f(b)f(a)ba\text{Average rate of change} = \frac{f(b) - f(a)}{b - a}

For this problem:

  • The function is f(x)=x28x+21f(x) = -x^2 - 8x + 21
  • The interval is [10,0][-10, 0], so a=10a = -10 and b=0b = 0

Step 1: Calculate f(10)f(-10)

= -100 + 80 + 21 = 1$$ ### Step 2: Calculate $$f(0)$$ $$f(0) = -(0)^2 - 8(0) + 21 = 21$$ ### Step 3: Apply the average rate of change formula $$\text{Average rate of change} = \frac{f(0) - f(-10)}{0 - (-10)} = \frac{21 - 1}{10} = \frac{20}{10} = 2$$ Thus, the average rate of change of the function over the interval $$[-10, 0]$$ is $$2$$. Would you like further details or clarification? Here are 5 related questions you might find helpful: 1. How is the average rate of change different from the instantaneous rate of change? 2. How does the quadratic nature of $$f(x) = -x^2 - 8x + 21$$ influence its rate of change? 3. Can the average rate of change ever be negative? 4. What does the sign of the average rate of change tell us about the behavior of the function? 5. How can we interpret the average rate of change in real-life scenarios involving quadratic functions? **Tip:** The average rate of change between two points gives the slope of the secant line connecting those points on the graph.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Rate of Change

Formulas

Average rate of change formula: (f(b) - f(a)) / (b - a)
Quadratic function: ax^2 + bx + c

Theorems

Average rate of change theorem for functions

Suitable Grade Level

Grades 9-11