Math Problem Statement

The functions f, of, xf(x), g, of, xg(x), and h, of, xh(x) are shown below. Select the option that represents the ordering of the functions according to their average rates of change on the interval 2, is less than or equal to, x, is less than or equal to, 62≤x≤6 goes from least to greatest. f, of, x f(x) x y xx g, of, xg(x) 22 77 33 1010 44 1515 55 2222 66 3131 77 4242 h, of, x, equals, x, squared, minus, x, plus, 28h(x)=x 2 −x+28 Answer Multiple Choice Answers g, of, x, comma, h, of, x, comma, f, of, xg(x),h(x),f(x) f, of, x, comma, g, of, x, comma, h, of, xf(x),g(x),h(x) g, of, x, comma, f, of, x, comma, h, of, xg(x),f(x),h(x) h, of, x, comma, f, of, x, comma, g, of, xh(x),f(x),g(x) f, of, x, comma, h, of, x, comma, g, of, xf(x),h(x),g(x) h, of, x, comma, g, of, x, comma, f, of, xh(x),g(x),f(x)

Solution

To find the correct ordering of the functions according to their average rates of change over the interval 2x62 \leq x \leq 6, we need to calculate the average rate of change for each function.

The formula for the average rate of change is:

Average rate of change=f(b)f(a)ba\text{Average rate of change} = \frac{f(b) - f(a)}{b - a} where f(x)f(x) is the function, and [a,b][a, b] is the interval (in this case, a=2a = 2 and b=6b = 6).

1. Function f(x)f(x):

From the table, we can see that for f(x)f(x):

  • f(2)=7f(2) = 7
  • f(6)=31f(6) = 31

Average rate of change for f(x)f(x): f(6)f(2)62=31762=244=6\frac{f(6) - f(2)}{6 - 2} = \frac{31 - 7}{6 - 2} = \frac{24}{4} = 6

2. Function g(x)g(x):

From the table, we can see that for g(x)g(x):

  • g(2)=7g(2) = 7
  • g(6)=31g(6) = 31

Average rate of change for g(x)g(x): g(6)g(2)62=31762=244=6\frac{g(6) - g(2)}{6 - 2} = \frac{31 - 7}{6 - 2} = \frac{24}{4} = 6 So, both f(x)f(x) and g(x)g(x) have the same average rate of change.

3. Function h(x)=x2x+28h(x) = x^2 - x + 28:

Now, let's calculate h(2)h(2) and h(6)h(6):

  • h(2)=222+28=42+28=30h(2) = 2^2 - 2 + 28 = 4 - 2 + 28 = 30
  • h(6)=626+28=366+28=58h(6) = 6^2 - 6 + 28 = 36 - 6 + 28 = 58

Average rate of change for h(x)h(x): h(6)h(2)62=583062=284=7\frac{h(6) - h(2)}{6 - 2} = \frac{58 - 30}{6 - 2} = \frac{28}{4} = 7

Ordering from least to greatest:

  • f(x)f(x) and g(x)g(x) both have an average rate of change of 6.
  • h(x)h(x) has an average rate of change of 7.

Thus, the order is f(x),g(x),h(x)f(x), g(x), h(x) from least to greatest.

Correct Answer:

The correct option is: f(x),g(x),h(x)\boxed{f(x), g(x), h(x)} or written as: f,g,hf, g, h.


Do you want more details or have any questions?

Here are 5 related questions:

  1. How do you calculate the average rate of change for a quadratic function?
  2. What is the difference between the rate of change of linear and quadratic functions?
  3. How does the average rate of change relate to the derivative of a function?
  4. How can you use the average rate of change to determine if a function is increasing or decreasing?
  5. How do you interpret the rate of change in real-world applications?

Tip: The average rate of change of a function over an interval is equivalent to the slope of the secant line connecting two points on the graph of the function within that interval.

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Math Problem Analysis

Mathematical Concepts

Average Rate of Change
Linear Functions
Quadratic Functions

Formulas

Average Rate of Change = (f(b) - f(a)) / (b - a)
h(x) = x² - x + 28

Theorems

Linear functions have a constant rate of change
Quadratic functions have a variable rate of change

Suitable Grade Level

Grades 8-10