Math Problem Statement

What is the average rate of change of f(x) over the interval [2,5]?

Solution

The average rate of change of a function f(x)f(x) over an interval [a,b][a, b] is given by the formula:

Average rate of change=f(b)f(a)ba\text{Average rate of change} = \frac{f(b) - f(a)}{b - a}

In your case, the interval is [2,5][2, 5]. So, we need to compute:

Average rate of change=f(5)f(2)52=f(5)f(2)3\text{Average rate of change} = \frac{f(5) - f(2)}{5 - 2} = \frac{f(5) - f(2)}{3}

To find the specific average rate of change, you'll need to know the values of f(2)f(2) and f(5)f(5).

Do you have those values, or do you know the function f(x)f(x)?

Would you like details or have any questions on this?

Here are 5 related questions you might consider:

  1. What is the formula for the function f(x)f(x)?
  2. How does the average rate of change relate to the derivative?
  3. Can you explain how to calculate instantaneous rates of change?
  4. What happens to the rate of change when the interval becomes very small?
  5. How would the average rate of change differ for a linear versus a quadratic function?

Tip: The average rate of change is equivalent to the slope of the secant line between the points (a,f(a))(a, f(a)) and (b,f(b))(b, f(b)) on the graph of f(x)f(x).

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Math Problem Analysis

Mathematical Concepts

Calculus
Rate of Change
Slope of a Secant Line

Formulas

Average rate of change = (f(b) - f(a)) / (b - a)

Theorems

Secant Line Theorem

Suitable Grade Level

Grades 10-12