Let’s address the questions based on the content in the images you uploaded:

3(A): Find the average rate of change in the number of teens with phones from age 15 to age 16.

The average rate of change is given by the formula:

$\text{Average Rate of Change} = \frac{\Delta y}{\Delta x} = \frac{\text{Change in Number of Teens}}{\text{Change in Age}}$

From the graph:

• At age 15, the number of teens = 341
• At age 16, the number of teens = 430

$\text{Rate of Change} = \frac{430 - 341}{16 - 15} = \frac{89}{1} = 89 \, \text{teens per year}.$

Answer: The average rate of change is 89 teens per year.

3(B): Find the average rate of change in the number of teens with phones from age 17 to age 18.

From the graph:

• At age 17, the number of teens = 580
• At age 18, the number of teens = 530

$\text{Rate of Change} = \frac{530 - 580}{18 - 17} = \frac{-50}{1} = -50 \, \text{teens per year}.$

Answer: The average rate of change is -50 teens per year.

4: Write an equation for the height of the bouncy ball.

The ball falls at a rate of 30 feet per second from an initial height of 8,000 feet. The height $h(t)$ at time $t$ (seconds) is given by:

$h(t) = 8000 - 30t$

where:

• $h(t)$ = height at time $t$,
• $8000$ = initial height,
• $30$ = rate of fall per second.

5: Graph the transformed function $g(x) = -|x| + 3$.

• The parent function $f(x) = |x|$ has a vertex at $(0, 0)$ and opens upward.
• The transformed function $g(x) = -|x| + 3$:
  • Negative sign reflects the graph over the x-axis.
  • +3 shifts the graph upward by 3 units.

Vertex: $(0, 3)$.

• The graph opens downward with slopes of $-1$ and $1$.

6: Graph the transformed function $h(x) = \sqrt{x + 2} - 1$.

• The parent function $f(x) = \sqrt{x}$ starts at $(0, 0)$.
• The transformed function $h(x) = \sqrt{x + 2} - 1$:
  • $x + 2$: Shifts the graph left by 2 units.
  • $-1$: Shifts the graph downward by 1 unit.

Starting point (vertex): $(-2, -1)$.

7(A): $\frac{3}{5} + \frac{4}{7}$

To add fractions, find a common denominator:

• LCD of 5 and 7 = 35.

[ \frac{3}{5} = \frac{21}{35}, \quad \frac{4