The average of the first $n$ natural numbers can be calculated using the formula:

$\text{Average} = \frac{\text{Sum of first } n \text{ natural numbers}}{n}$

The sum of the first $n$ natural numbers is given by:

$\text{Sum} = \frac{n \times (n + 1)}{2}$

For $n = 60$:

$\text{Sum} = \frac{60 \times 61}{2} = 1830$

So, the average is:

$\text{Average} = \frac{1830}{60} = 30.5$

Thus, the correct answer is:

c. 30.5

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Related Questions:

1. What is the average of the first 100 natural numbers?
2. What is the sum of the first 50 natural numbers?
3. How would you find the average of the first 60 even numbers?
4. How does the average of natural numbers compare to that of consecutive integers starting from 10?
5. What is the formula for the sum of the first $n$ odd natural numbers?

Tip: To find the average of the first $n$ natural numbers, simply use the formula $\frac{n+1}{2}$.