Math Problem Statement

In a certain country, everyone in the labor force in the year 2000 had 12 years of education. In

1950 everyone in the labor force had 4 years of education. What was the average annual growth

in income per worker that was due to the increase in education?

Solution

To calculate the average annual growth in income per worker due to the increase in education, we need to apply the concept of the Mincer earnings function, which relates the percentage increase in income to the years of education. The general form of this function is:

Income growth=erΔE1\text{Income growth} = e^{r \cdot \Delta E} - 1

where:

  • rr is the return on education (typically around 0.10, which corresponds to a 10% increase in income for each additional year of education),
  • ΔE\Delta E is the change in the average years of education (from 4 years to 12 years in this case).

We are given that the years of education increased from 4 to 12 years, so ΔE=124=8\Delta E = 12 - 4 = 8 years.

Step-by-step calculation:

  1. Return on education:
    Assuming the standard return on education is 10%, or r=0.10r = 0.10.

  2. Change in education:
    ΔE=124=8\Delta E = 12 - 4 = 8 years.

  3. Income growth formula: Income growth=e0.1081\text{Income growth} = e^{0.10 \cdot 8} - 1

  4. Calculate e0.108e^{0.10 \cdot 8}: e0.802.2255e^{0.80} \approx 2.2255

  5. Final income growth: Income growth=2.22551=1.2255 or 122.55%\text{Income growth} = 2.2255 - 1 = 1.2255 \text{ or } 122.55\%

So, due to the increase in education, income per worker increased by approximately 122.55% over the period from 1950 to 2000.

Average Annual Growth Rate:

Next, to find the average annual growth rate over this 50-year period, we use the formula for average annual growth rate:

Average annual growth rate=(1+Total growth100)1/t1\text{Average annual growth rate} = \left( 1 + \frac{\text{Total growth}}{100} \right)^{1/t} - 1

where:

  • Total growth = 122.55%
  • t=50t = 50 years.

Average annual growth rate=(1+122.55100)1/501\text{Average annual growth rate} = \left( 1 + \frac{122.55}{100} \right)^{1/50} - 1

Simplifying:

Average annual growth rate=(2.2255)1/5010.0164 or 1.64%\text{Average annual growth rate} = \left( 2.2255 \right)^{1/50} - 1 \approx 0.0164 \text{ or } 1.64\%

Conclusion:

The average annual growth in income per worker due to the increase in education is approximately 1.64%.


Would you like more details on the formula used or have any further questions?

Here are 5 related questions:

  1. How does the return on education vary across different countries?
  2. What impact does the quality of education have on income growth?
  3. Can we calculate income growth with different rates of return on education?
  4. How would an increase in education inequality affect income distribution?
  5. What other factors besides education influence income growth?

Tip: The Mincer earnings function is a simplified model and assumes that the return to education is constant, but in reality, returns may differ based on education quality, job sector, and region.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Mincer Earnings Function
Percentage Growth

Formulas

Income growth = e^{r \cdot \Delta E} - 1
Average annual growth rate = \left(1 + \frac{Total Growth}{100}\right)^{1/t} - 1

Theorems

Mincer Earnings Function

Suitable Grade Level

Grades 10-12