23.9850 amu + 24.9858 amu + 25.9826 amu/3

The given expression is:

\[
23.9850 \, \text{amu} + 24.9858 \, \text{amu} + \frac{25.9826 \, \text{amu}}{3}
\]

Let's break it down step by step:

1. First, divide \(25.9826 \, \text{amu}\) by 3:

\[
\frac{25.9826 \, \text{amu}}{3} = 8.6609 \, \text{amu}
\]

2. Now, add \(23.9850 \, \text{amu}\), \(24.9858 \, \text{amu}\), and \(8.6609 \, \text{amu}\):

\[
23.9850 \, \text{amu} + 24.9858 \, \text{amu} + 8.6609 \, \text{amu} = 57.6317 \, \text{amu}
\]

Thus, the result is:

\[
57.6317 \, \text{amu}
\]

Let me know if you'd like any additional explanation or have questions!

Here are 5 related questions for further practice:
1. What is the result of \(30.0150 \, \text{amu} + 27.9850 \, \text{amu} + \frac{24.9825 \, \text{amu}}{3}\)?
2. How do you calculate the weighted average of atomic masses?
3. Can you explain how atomic mass units (amu) are defined?
4. What is the atomic mass of an element with isotope masses of 12.000 amu, 13.003 amu, and 14.002 amu with 90%, 5%, and 5% abundance?
5. How do you convert atomic mass units to grams?

**Tip**: When adding or subtracting values, pay attention to the number of significant figures to ensure precision.

Explore the detailed solution for calculating the sum of atomic masses: 23.9850 amu + 24.9858 amu + 25.9826 amu divided by 3. This problem involves basic arithmetic operations such as addition and division. Perfect for students in Grades 6-8 learning about atomic mass and basic operations.

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