Math Problem Statement

Show that (π‘₯ + 𝑦) + 𝑧 = π‘₯ + (𝑦 + 𝑧) for all π‘₯, 𝑦, 𝑧 ∈ 𝐅^n

Solution

To prove that (x+y)+z=x+(y+z)(x + y) + z = x + (y + z) for all vectors x,y,z∈Fnx, y, z \in \mathbb{F}^n, we need to show that vector addition is associative in the vector space Fn\mathbb{F}^n. Here's the step-by-step proof:

Given:

  • x=(x1,x2,…,xn)x = (x_1, x_2, \ldots, x_n)
  • y=(y1,y2,…,yn)y = (y_1, y_2, \ldots, y_n)
  • z=(z1,z2,…,zn)z = (z_1, z_2, \ldots, z_n) where x,y,zx, y, z are vectors in Fn\mathbb{F}^n, the vector space of nn-tuples over a field F\mathbb{F}.

Step 1: Vector addition in Fn\mathbb{F}^n

The addition of two vectors in Fn\mathbb{F}^n is defined component-wise. For vectors x=(x1,x2,…,xn)x = (x_1, x_2, \dots, x_n) and y=(y1,y2,…,yn)y = (y_1, y_2, \dots, y_n), their sum is: x+y=(x1+y1,x2+y2,…,xn+yn)x + y = (x_1 + y_1, x_2 + y_2, \dots, x_n + y_n)

Step 2: Express both sides of the equation

Left-hand side: (x+y)+z(x + y) + z

First, compute x+yx + y: x+y=(x1+y1,x2+y2,…,xn+yn)x + y = (x_1 + y_1, x_2 + y_2, \dots, x_n + y_n) Now, add z=(z1,z2,…,zn)z = (z_1, z_2, \dots, z_n) to this result: (x+y)+z=((x1+y1)+z1,(x2+y2)+z2,…,(xn+yn)+zn)(x + y) + z = ((x_1 + y_1) + z_1, (x_2 + y_2) + z_2, \dots, (x_n + y_n) + z_n)

Right-hand side: x+(y+z)x + (y + z)

First, compute y+zy + z: y+z=(y1+z1,y2+z2,…,yn+zn)y + z = (y_1 + z_1, y_2 + z_2, \dots, y_n + z_n) Now, add x=(x1,x2,…,xn)x = (x_1, x_2, \dots, x_n) to this result: x+(y+z)=(x1+(y1+z1),x2+(y2+z2),…,xn+(yn+zn))x + (y + z) = (x_1 + (y_1 + z_1), x_2 + (y_2 + z_2), \dots, x_n + (y_n + z_n))

Step 3: Use associativity of addition in the field F\mathbb{F}

Since addition in the field F\mathbb{F} is associative, we know that for any elements a,b,c∈Fa, b, c \in \mathbb{F}: (a+b)+c=a+(b+c)(a + b) + c = a + (b + c) Applying this to each component of the vectors, we get: (xi+yi)+zi=xi+(yi+zi)(x_i + y_i) + z_i = x_i + (y_i + z_i) for all i=1,2,…,ni = 1, 2, \dots, n.

Step 4: Conclusion

Since the equality (xi+yi)+zi=xi+(yi+zi)(x_i + y_i) + z_i = x_i + (y_i + z_i) holds for each component ii, we conclude that: (x+y)+z=x+(y+z)(x + y) + z = x + (y + z) Thus, vector addition is associative in Fn\mathbb{F}^n.

Would you like further details on this proof?

Related Questions:

  1. What is the definition of a vector space over a field F\mathbb{F}?
  2. Why is associativity important in vector spaces?
  3. Can you show the proof for the commutativity of vector addition?
  4. How does this associativity property extend to infinite-dimensional vector spaces?
  5. What is the role of the field F\mathbb{F} in defining the properties of Fn\mathbb{F}^n?

Tip:

Always check if operations (like addition or multiplication) are associative, commutative, or distributive when working with abstract algebraic structures such as vector spaces!

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Vector Spaces
Associative Property
Field

Formulas

(x + y) + z = x + (y + z) for all x, y, z ∈ F^n

Theorems

Associativity of vector addition in F^n
Associativity of addition in a field

Suitable Grade Level

Undergraduate (Introductory Linear Algebra)