The exercise asks to arrange the numbers in descending order. Here's a list of the numbers:

1. $3.05$
2. $1.5$
3. $1$
4. $\sqrt{7}$
5. $-4.32$
6. $-\sqrt{8}$

Let's first evaluate the approximate values of the square roots:

• $\sqrt{7} \approx 2.65$
• $\sqrt{8} \approx 2.83$

Now we have the numbers as:

• $3.05$
• $1.5$
• $1$
• $2.65$ (which is $\sqrt{7}$)
• $-4.32$
• $-2.83$ (which is $-\sqrt{8}$)

Now, we arrange these values in descending order:

• $3.05$
• $2.65$ ( $\sqrt{7}$ )
• $1.5$
• $1$
• $-2.83$ ( $-\sqrt{8}$ )
• $-4.32$

The answer is: Order (from largest to smallest): $3.05, \sqrt{7}, 1.5, 1, -\sqrt{8}, -4.32$.

Would you like a deeper explanation for any part of this solution?

Here are 5 related questions for practice:

1. Arrange $\sqrt{2}, \sqrt{5}, 2.5, -1, -\sqrt{3}$ in descending order.
2. Simplify and compare $\sqrt{3}$ and $\sqrt{8}$.
3. Calculate the exact decimal approximation of $\sqrt{11}$.
4. How do square roots of non-perfect squares behave in comparison to integers?
5. Compare $\sqrt{9.5}$ and $3.2$.

Tip: When comparing square roots, it's often useful to approximate their decimal values first!