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Let's solve the problems related to the given arithmetic sequence:

The arithmetic sequence provided is \( 12, 19, 26, 33, \ldots \).

### Part (a): Find the 8th term of the sequence.
To find the \(n\)th term of an arithmetic sequence, we use the formula:
\[
a_n = a_1 + (n-1) \cdot d
\]
where:
- \(a_n\) is the \(n\)th term,
- \(a_1\) is the first term,
- \(d\) is the common difference.

Given:
- \(a_1 = 12\),
- The common difference \(d = 19 - 12 = 7\).

For the 8th term (\(n = 8\)):
\[
a_8 = 12 + (8-1) \cdot 7 = 12 + 7 \cdot 7 = 12 + 49 = 61
\]

So, the 8th term is **61**.

### Part (b): Find the sum of the first 10 terms of the sequence.
The sum of the first \(n\) terms of an arithmetic sequence is given by:
\[
S_n = \frac{n}{2} \cdot (2a_1 + (n-1) \cdot d)
\]

For the first 10 terms (\(n = 10\)):
\[
S_{10} = \frac{10}{2} \cdot (2 \cdot 12 + (10-1) \cdot 7)
\]
\[
S_{10} = 5 \cdot (24 + 63) = 5 \cdot 87 = 435
\]

So, the sum of the first 10 terms is **435**.

### Part (c): The sum of the first \(n\) terms is 915. Find the value of \(n\).
We use the sum formula again, but now solve for \(n\):
\[
S_n = \frac{n}{2} \cdot (2a_1 + (n-1) \cdot d)
\]
Given:
\[
915 = \frac{n}{2} \cdot (24 + (n-1) \cdot 7)
\]
\[
915 = \frac{n}{2} \cdot (24 + 7n - 7)
\]
\[
915 = \frac{n}{2} \cdot (7n + 17)
\]
Multiply both sides by 2 to eliminate the fraction:
\[
1830 = n \cdot (7n + 17)
\]
Expanding and rearranging the equation:
\[
7n^2 + 17n - 1830 = 0
\]
This is a quadratic equation. To solve it, we can use the quadratic formula:
\[
n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
where \(a = 7\), \(b = 17\), and \(c = -1830\).

\[
n = \frac{-17 \pm \sqrt{17^2 + 4 \cdot 7 \cdot 1830}}{2 \cdot 7}
\]
\[
n = \frac{-17 \pm \sqrt{289 + 51240}}{14}
\]
\[
n = \frac{-17 \pm \sqrt{51529}}{14}
\]
\[
n = \frac{-17 \pm 227}{14}
\]
Taking the positive root:
\[
n = \frac{210}{14} = 15
\]

So, \(n = 15\).

If you have any questions or need further details, feel free to ask!

Here are 5 related questions:
1. How would the common difference change the sequence if it were 5 instead of 7?
2. What is the 20th term of this arithmetic sequence?
3. How do you find the sum of the first 50 terms of an arithmetic sequence?
4. Can you derive the formula for the sum of an arithmetic sequence from first principles?
5. How does the sum formula change if the sequence starts at a different term?

**Tip:** When dealing with sequences, always check the pattern of the common difference (arithmetic) or ratio (geometric) to ensure you're applying the correct formula.

Consider the arithmetic sequence 12, 19, 26, 33, ....
a. Find the 8th term of the sequence.
b. Find the sum of the first 10 terms of the sequence.
c. The sum of the first n terms is 915. Find the value of n.

Solve arithmetic sequence problems including finding the 8th term, the sum of the first 10 terms, and determining n for a given sum. Learn the application of arithmetic sequence formulas and quadratic equations. Suitable for Grades 8-10.

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