Math Problem Statement

Write a sequence that is an arithmetic sequence. State the common difference, and find a6.

Solution

Let's create an arithmetic sequence:

Example sequence:
4, 8, 12, 16, 20, ...

1. Common Difference (d):

The common difference dd is the difference between any two consecutive terms.
For example, d=84=4d = 8 - 4 = 4, and d=128=4d = 12 - 8 = 4, so the common difference is d=4d = 4.

2. Finding a6a_6:

The general formula for the nn-th term of an arithmetic sequence is: an=a1+(n1)da_n = a_1 + (n - 1) \cdot d Where:

  • ana_n is the nn-th term
  • a1a_1 is the first term
  • dd is the common difference
  • nn is the position of the term

To find a6a_6, we substitute the known values into the formula:

  • a1=4a_1 = 4 (the first term)
  • d=4d = 4 (the common difference)
  • n=6n = 6

a6=4+(61)4a_6 = 4 + (6 - 1) \cdot 4 a6=4+54a_6 = 4 + 5 \cdot 4 a6=4+20a_6 = 4 + 20 a6=24a_6 = 24

So, a6=24a_6 = 24.

Summary:

  • Arithmetic Sequence: 4, 8, 12, 16, 20, ...
  • Common Difference (d): 4
  • a6a_6: 24

Would you like more details or have any questions on this?
Here are some related questions:

  1. How do you find the nn-th term of an arithmetic sequence?
  2. What happens if the common difference is negative?
  3. How can you find the sum of the first nn terms in an arithmetic sequence?
  4. How do you recognize an arithmetic sequence in a real-world situation?
  5. Can an arithmetic sequence have a common difference of zero?

Tip: In an arithmetic sequence, the common difference remains constant, making it easy to predict future terms.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Patterns in Sequences
Algebra

Formulas

General formula for the n-th term of an arithmetic sequence: an = a1 + (n - 1) * d

Theorems

Arithmetic progression properties

Suitable Grade Level

Grades 6-8