Math Problem Statement

Make an Arithmetic Sequence by arranging 4 of the numbers: 42, 31, 19, 15, 25, and 37. Find the common difference and the 15th term.

Solution

The image presents a problem about creating an arithmetic sequence using a selection of four numbers from a given set: 42, 31, 19, 15, 25, and 37. The goal is to create an increasing sequence and calculate the common difference as well as the 15th term of the sequence using the arithmetic sequence formula.

Step 1: Identify an Arithmetic Sequence

An arithmetic sequence has the property that the difference between consecutive terms is constant. We need to select 4 numbers from the given set that can form such a sequence.

Looking at the numbers:

  • 15, 19, 25, and 31 form an arithmetic sequence with a common difference of 6.

Sequence: 15, 19, 25, 31.

Step 2: Common Difference

The common difference dd is the difference between any two consecutive terms in the arithmetic sequence. From the sequence above: [ d = 19 - 15 = 4, \quad 25 - 19 = 6, \quad 31-25 = 6

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Algebra

Formulas

u_n = u_1 + (n - 1) * d

Theorems

Arithmetic sequence common difference

Suitable Grade Level

Grades 8-10