Math Problem Statement

Solve given 4

Solve for the first few terms of an arithmetic sequence with a = 0.13 and d = 0.5.

Solution

For question 4, the values given are:

  • a=0.13a = 0.13 (first term of the arithmetic sequence)
  • d=0.5d = 0.5 (common difference)

The general formula for the nn-th term of an arithmetic sequence is:

an=a+(n1)da_n = a + (n - 1) \cdot d

Where:

  • ana_n is the nn-th term,
  • aa is the first term,
  • dd is the common difference,
  • nn is the term number.

Let's calculate the first few terms of the sequence:

  1. a1=a=0.13a_1 = a = 0.13
  2. a2=0.13+(21)0.5=0.13+0.5=0.63a_2 = 0.13 + (2 - 1) \cdot 0.5 = 0.13 + 0.5 = 0.63
  3. a3=0.13+(31)0.5=0.13+1.0=1.13a_3 = 0.13 + (3 - 1) \cdot 0.5 = 0.13 + 1.0 = 1.13
  4. a4=0.13+(41)0.5=0.13+1.5=1.63a_4 = 0.13 + (4 - 1) \cdot 0.5 = 0.13 + 1.5 = 1.63
  5. a5=0.13+(51)0.5=0.13+2.0=2.13a_5 = 0.13 + (5 - 1) \cdot 0.5 = 0.13 + 2.0 = 2.13

Would you like to see more terms or any additional details about this process?

Here are 5 related questions:

  1. How can you find the sum of the first nn terms in an arithmetic sequence?
  2. What is the general form of an arithmetic progression?
  3. How does the common difference dd affect the growth of the sequence?
  4. Can you reverse the process to find aa if ana_n and nn are known?
  5. How do geometric sequences differ from arithmetic sequences?

Tip: In arithmetic sequences, the difference between consecutive terms is always constant, making it easy to calculate any term or sum using the correct formulas.