Math Problem Statement

find the first five terms of the sequence a(n)=5n + 4

Solution

To find the first five terms of the sequence defined by the formula a(n)=5n+4a(n) = 5n + 4, we need to evaluate the expression for n=1,2,3,4,n = 1, 2, 3, 4, and 55.

Let's calculate each term:

  1. For n=1n = 1: a(1)=5×1+4=5+4=9a(1) = 5 \times 1 + 4 = 5 + 4 = 9

  2. For n=2n = 2: a(2)=5×2+4=10+4=14a(2) = 5 \times 2 + 4 = 10 + 4 = 14

  3. For n=3n = 3: a(3)=5×3+4=15+4=19a(3) = 5 \times 3 + 4 = 15 + 4 = 19

  4. For n=4n = 4: a(4)=5×4+4=20+4=24a(4) = 5 \times 4 + 4 = 20 + 4 = 24

  5. For n=5n = 5: a(5)=5×5+4=25+4=29a(5) = 5 \times 5 + 4 = 25 + 4 = 29

Thus, the first five terms of the sequence are:

9,14,19,24,299, 14, 19, 24, 29

Would you like a detailed explanation or have any other questions?

Related Questions:

  1. What is the 10th term of the sequence a(n)=5n+4a(n) = 5n + 4?
  2. How can we determine if a number is in the sequence a(n)=5n+4a(n) = 5n + 4?
  3. What is the sum of the first 20 terms of the sequence a(n)=5n+4a(n) = 5n + 4?
  4. How does the sequence change if the formula becomes a(n)=5n4a(n) = 5n - 4?
  5. How can we express the nn-th term formula if the sequence has a common difference of 7 instead of 5?

Tip: To find any term in an arithmetic sequence, use the formula a(n)=a1+(n1)da(n) = a_1 + (n-1)d, where a1a_1 is the first term and dd is the common difference.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences

Formulas

Arithmetic sequence formula: a(n) = a₁ + (n-1)d

Theorems

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Suitable Grade Level

Grades 7-9