The problem asks us to find the 14th term of an arithmetic sequence where:

• The first term ($a_1$) is $7$,
• The common difference ($d$) is $-3$.

The formula for the $n$th term of an arithmetic sequence is:

$a_n = a_1 + (n-1) \cdot d$

Substitute the given values:

$a_{14} = 7 + (14-1) \cdot (-3)$

Simplify:

$a_{14} = 7 + 13 \cdot (-3)$ $a_{14} = 7 - 39$ $a_{14} = -32$

Thus, the answer is: $\text{A. } -32$

Would you like a detailed explanation of the steps or help with related concepts? Here are five follow-up questions:

1. How can the general formula for arithmetic sequences be derived?
2. What happens if the common difference ($d$) is positive instead of negative?
3. Can you derive the sum of the first $n$ terms of this sequence?
4. How does the position ($n$) affect the growth or decline of the sequence?
5. What are some real-world examples of arithmetic sequences?

Tip: Always double-check calculations when working with negative numbers to avoid errors!