Math Problem Statement

Find the indicated area under the curve of the standard normal distribution; then convert it to a percentage and fill in the blank. About ____% of the area between z = -1 and z = 1 ( or within 1 standard deviation of the mean). DONT round answer

Solution

To find the area under the curve of the standard normal distribution between z=1z = -1 and z=1z = 1, we will use the properties of the cumulative distribution function (CDF) for the standard normal distribution.

The area between z=1z = -1 and z=1z = 1 is the difference between the cumulative probabilities at z=1z = 1 and z=1z = -1. Using the CDF values for a standard normal distribution:

P(z1)=0.8413447461P(z \leq 1) = 0.8413447461 P(z1)=0.1586552539P(z \leq -1) = 0.1586552539

Now, the area between z=1z = -1 and z=1z = 1 is:

Area=P(z1)P(z1)=0.84134474610.1586552539=0.6826894922\text{Area} = P(z \leq 1) - P(z \leq -1) = 0.8413447461 - 0.1586552539 = 0.6826894922

To convert this to a percentage, we multiply by 100:

Percentage=0.6826894922×100=68.26894922%\text{Percentage} = 0.6826894922 \times 100 = 68.26894922\%

Thus, about 68.26894922% of the area is between z=1z = -1 and z=1z = 1 (or within 1 standard deviation of the mean).

Would you like more details on this, or have any questions?

Here are 5 related questions:

  1. What is the area under the curve between z=2z = -2 and z=2z = 2?
  2. How do you calculate the area for non-standard normal distributions?
  3. What percentage of the area lies outside of z=1z = -1 and z=1z = 1?
  4. What does it mean for a normal distribution to be “standard”?
  5. How do you calculate the CDF for any zz-value?

Tip: The standard normal distribution has a mean of 0 and a standard deviation of 1, making it a great reference for probabilities in other normal distributions.

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Math Problem Analysis

Mathematical Concepts

Statistics
Standard Normal Distribution
Probability

Formulas

P(z ≤ 1) - P(z ≤ -1)
Area = 0.8413447461 - 0.1586552539
Percentage = Area × 100

Theorems

Empirical Rule (68-95-99.7 Rule)

Suitable Grade Level

Grades 10-12