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The problem requires us to find the area of the shaded region in a rectangle placed around a semicircle. Let me break it down step by step:

### 1. **Given Information:**
   - The length of the rectangle (which is also the diameter of the semicircle) = 8 yards.
   - We are asked to use \( \pi = 3.14 \).
   - The goal is to find the area of the shaded region, which is the area of the rectangle minus the area of the semicircle.

### 2. **Finding the Area of the Rectangle:**
   - The length of the rectangle = 8 yards.
   - The width of the rectangle is the same as the radius of the semicircle, which is half of the diameter:
     \[
     \text{Radius} = \frac{8}{2} = 4 \text{ yards}.
     \]
   - The area of the rectangle is:
     \[
     A_{\text{rectangle}} = \text{length} \times \text{width} = 8 \times 4 = 32 \text{ square yards}.
     \]

### 3. **Finding the Area of the Semicircle:**
   - The formula for the area of a full circle is \( \pi r^2 \).
   - For a semicircle, the area is half of that:
     \[
     A_{\text{semicircle}} = \frac{1}{2} \times \pi \times r^2 = \frac{1}{2} \times 3.14 \times 4^2 = \frac{1}{2} \times 3.14 \times 16 = 25.12 \text{ square yards}.
     \]

### 4. **Finding the Area of the Shaded Region:**
   - The shaded region is the area of the rectangle minus the area of the semicircle:
     \[
     A_{\text{shaded}} = A_{\text{rectangle}} - A_{\text{semicircle}} = 32 - 25.12 = 6.88 \text{ square yards}.
     \]

### Final Answer:
The area of the shaded region is **6.88 square yards**.

Do you need further clarification or have any additional questions?

Here are 5 related questions you might explore:
1. How would the shaded area change if the diameter of the semicircle was different?
2. What if the shape was a quarter circle instead of a semicircle?
3. How can the formula for the area of a semicircle be derived geometrically?
4. What happens to the shaded area if the width of the rectangle is increased?
5. How does the use of different values for \( \pi \) affect the result?

**Tip:** When subtracting areas, always ensure that both areas are calculated with consistent units and dimensions.

A rectangle is placed around a semicircle as shown below. The length of the rectangle is 8 yards. Find the area of the shaded region. Use 3.14 for π, and do not round your answer.

This problem involves calculating the area of the shaded region formed by a rectangle placed around a semicircle. Using a rectangle of length 8 yards and π = 3.14, this solution demonstrates the steps needed to find the area of the rectangle and the semicircle, followed by subtracting the areas. Suitable for students in Grades 6-8.

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