https://file.aiquickdraw.com/mathbot/file/1727107609740vd864lrp.jpg

The triangle in the image is a right triangle, and its area can be calculated using the formula for the area of a triangle:

\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]

Here:
- The base of the triangle is 16 mm.
- The height of the triangle is 20 mm.

Now, applying the values:

\[
\text{Area} = \frac{1}{2} \times 16 \, \text{mm} \times 20 \, \text{mm}
\]

\[
\text{Area} = \frac{1}{2} \times 320 \, \text{mm}^2 = 160 \, \text{mm}^2
\]

Thus, the area of the triangle is **160 mm²**.

Would you like a detailed explanation of how this formula works or why it's applicable here? 

### Relative Questions:
1. How do you calculate the area of non-right triangles?
2. What is the difference between base and height in non-right-angled triangles?
3. How would the area change if the triangle's base or height was doubled?
4. What if you know the sides of a triangle but not its height—how do you calculate the area?
5. Can the Pythagorean theorem help in finding the area of a triangle?

### Tip:
In a right triangle, the two legs always act as the base and height when calculating the area!

Learn how to calculate the area of a right triangle with a base of 16 mm and a height of 20 mm. The solution uses the area of a triangle formula, (1/2) × base × height, and explains the step-by-step process. This is suitable for students in Grades 6-8.

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