Math Problem Statement

What is the area of a rectangle with a width of 3x and length of (2x^2 + 4x)?

Solution

I see that you've uploaded an image containing a math question. Let me read it for you:

The question is: What is the area of a rectangle with a width of 3x3x and length of (2x2+4x)(2x^2 + 4x)?

To find the area of a rectangle:

The formula for the area AA of a rectangle is: A=width×lengthA = \text{width} \times \text{length}

In this case:

  • Width = 3x3x
  • Length = 2x2+4x2x^2 + 4x

Now multiply these terms:

A=3x×(2x2+4x)A = 3x \times (2x^2 + 4x)

Use the distributive property to multiply: A=3x×2x2+3x×4xA = 3x \times 2x^2 + 3x \times 4x A=6x3+12x2A = 6x^3 + 12x^2

So, the area of the rectangle is: A=6x3+12x2A = 6x^3 + 12x^2

Now, the correct option should be the one showing 6x3+12x26x^3 + 12x^2.

Would you like more details or further clarification?

Relative Questions:

  1. What is the area formula for different shapes like triangles and circles?
  2. How do you apply the distributive property to algebraic expressions?
  3. What are the different properties of exponents?
  4. How does factoring polynomials relate to finding areas?
  5. Can we express the area in terms of factored form?

Tip:

Always double-check algebraic multiplications using the distributive property to ensure that all terms are correctly accounted for.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Polynomial Multiplication

Formulas

Area of a rectangle: A = width × length
Distributive property: a(b + c) = ab + ac

Theorems

-

Suitable Grade Level

Grades 8-10