https://file.aiquickdraw.com/mathbot/file/1727990706750pqh6sqqh.jpg

The given image contains a trapezoid with the following dimensions:
- The top base is 16 inches.
- The bottom base is 8.3 inches.
- The height is 6.6 inches.

To find the area of a trapezoid, we use the formula:

\[
A = \frac{1}{2} \times (b_1 + b_2) \times h
\]

Where:
- \( b_1 \) and \( b_2 \) are the lengths of the two parallel sides (bases),
- \( h \) is the height.

Substituting the given values:
\[
A = \frac{1}{2} \times (16 + 8.3) \times 6.6
\]
\[
A = \frac{1}{2} \times 24.3 \times 6.6
\]
\[
A = \frac{1}{2} \times 160.38
\]
\[
A = 80.19 \, \text{square inches}
\]

So, the area of the trapezoid is approximately **80.19 square inches**.

Would you like more details or have any questions? Here are some related questions to think about:

1. How do we calculate the perimeter of the same trapezoid?
2. Can the formula for the area of a trapezoid be applied to other shapes?
3. What is the relationship between a trapezoid and a parallelogram?
4. How would the area change if the height were doubled but the bases stayed the same?
5. What if the trapezoid had an additional non-right angle—how would you calculate its area?

**Tip:** Always ensure that the height you use in trapezoid area calculations is perpendicular to the two parallel sides (bases).

What is the area, in square inches, of the trapezoid below? (Top base: 16 in, Bottom base: 8.3 in, Height: 6.6 in)

Learn how to find the area of a trapezoid with a top base of 16 inches, bottom base of 8.3 inches, and height of 6.6 inches using the trapezoid area formula. This problem covers essential geometric concepts, ideal for students in Grades 6-8.

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