A rhombus is inscribed inside a circle, and its perimeter is 2424. If the area of the circle is AπAπ, find AA. 

Given a rhombus inscribed inside a circle, we are tasked with finding the value of \( A \) if the perimeter of the rhombus is \( 2424 \) and the area of the circle is \( A\pi \).

### Step 1: Analyzing the Rhombus and the Circle
When a rhombus is inscribed in a circle, it implies that the rhombus is a special type of rhombus known as a **square**, since all four sides are equal, and the diagonals of the rhombus are diameters of the circle. The key reason is that the only quadrilateral where diagonals are equal and bisect at 90 degrees (as required for inscribing in a circle) is a square.

### Step 2: Calculating the Side Length of the Rhombus
The perimeter of the rhombus (which is now a square) is given as \( 2424 \). Since the perimeter of a square is four times the length of one side, we can find the side length \( s \) by dividing the perimeter by 4:

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A rhombus is inscribed inside a circle, and its perimeter is 2424. If the area of the circle is Aπ, find A.

Learn how to solve a problem where a rhombus inscribed in a circle is actually a square, with a perimeter of 2424. This problem covers key geometric concepts, including perimeter, area of a circle, and properties of squares and rhombuses. Suitable for students in Grades 10-12.

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