Given a rhombus inscribed inside a circle, we are tasked with finding the value of $A$ if the perimeter of the rhombus is $2424$ and the area of the circle is $A\pi$.

Step 1: Analyzing the Rhombus and the Circle

When a rhombus is inscribed in a circle, it implies that the rhombus is a special type of rhombus known as a square, since all four sides are equal, and the diagonals of the rhombus are diameters of the circle. The key reason is that the only quadrilateral where diagonals are equal and bisect at 90 degrees (as required for inscribing in a circle) is a square.

Step 2: Calculating the Side Length of the Rhombus

The perimeter of the rhombus (which is now a square) is given as $2424$. Since the perimeter of a square is four times the length of one side, we can find the side length $s$ by dividing the perimeter by 4:

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