To solve this problem:

The diameter of the circle is 16 mm. The formula for the area $A$ of a circle is given by:

$A = \pi r^2$

where $r$ is the radius of the circle. The radius is half of the diameter, so:

$r = \frac{16}{2} = 8 \, \text{mm}$

Now substitute the radius into the area formula:

$A = \pi (8)^2 = \pi \times 64 = 64\pi \, \text{mm}^2$

So, the area of the circle is:

$64\pi \, \text{mm}^2$

Would you like more details or have any questions?

Here are 5 follow-up questions:

1. How would you calculate the circumference of the circle given its diameter?
2. If the radius was doubled, how would that affect the area?
3. What would the area be if the diameter was given in centimeters instead of millimeters?
4. How would you express the area if you needed a numerical approximation using $\pi \approx 3.1416$?
5. How does the area of a circle change if only the diameter is changed?

Tip: The radius is always half the diameter—keep this relationship in mind when solving circle-related problems!