To solve this problem, we'll calculate the areas of the individual shapes (Rectangle A and Triangle B) and then add them together to find the area of the entire figure.

Step 1: Find the area of Rectangle A

• Length of the rectangle (base): 9 units
• Height of the rectangle: 5 units

The formula for the area of a rectangle is: $\text{Area} = \text{base} \times \text{height}$ $\text{Area of Rectangle A} = 9 \times 5 = 45 \text{ square units}$

Step 2: Find the area of Triangle B

• Base of the triangle: 13 - 9 = 4 units (since the total length is 13 units, and the rectangle covers 9 units)
• Height of the triangle: 5 units

The formula for the area of a triangle is: $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$ $\text{Area of Triangle B} = \frac{1}{2} \times 4 \times 5 = 10 \text{ square units}$

Step 3: Find the area of the whole figure

The whole figure consists of Rectangle A and Triangle B, so we add their areas: $\text{Total Area} = 45 + 10 = 55 \text{ square units}$

Summary

Figure	Area (square units)
Rectangle A	45
Triangle B	10
Whole figure	55

Would you like further details or have any questions?

Related Questions

1. How do you find the area of composite shapes?
2. What is the difference between the area of a rectangle and a parallelogram?
3. How do you calculate the area of a trapezoid?
4. What are other ways to split a quadrilateral into simpler shapes?
5. How would the total area change if the height was doubled?

Tip

When dealing with composite shapes, break them down into familiar shapes (like rectangles and triangles) to make finding the area easier.