Math Problem Statement

Find the area A of the region that is bounded between the curve f(x)=ln(x)+1 and the line g(x)=−4xe+6 over the interval [1,4].

Solution

To find the area AA of the region bounded between the curve f(x)=ln(x)+1f(x) = \ln(x) + 1 and the line g(x)=4x+6g(x) = -4x + 6 over the interval [1,4][1, 4], we follow these steps:

Step 1: Set up the area formula

The area between two curves f(x)f(x) and g(x)g(x) over the interval [a,b][a, b] is given by: A=ab(f(x)g(x))dxA = \int_a^b \left( f(x) - g(x) \right) dx Here, f(x)=ln(x)+1f(x) = \ln(x) + 1 and g(x)=4x+6g(x) = -4x + 6.

Step 2: Write the integral

The area AA is: A=14((ln(x)+1)(4x+6))dxA = \int_1^4 \left( (\ln(x) + 1) - (-4x + 6) \right) dx

Simplifying the integrand: [ (\ln(x) + 1) - (-4x + 6) = \ln(x) + 1 +

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Math Problem Analysis

Mathematical Concepts

Calculus
Definite Integrals
Area Between Curves

Formulas

A = ∫_a^b (f(x) - g(x)) dx

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

Grades 11-12 or College Level