The fifth Maclaurin polynomial for e^(2x) and e^-(2x) are P(x) = = (((x+3) x + )x+2)x + 2)x + 1 Approximate e-0.98 using 1/(P(0.49) )and four-digit rounding arithmetic. Compute the absolute and relative error
Solution
To approximate e−0.98 using the given fifth Maclaurin polynomial for e2x and its transformation, we need to follow these steps:
Construct the fifth Maclaurin polynomial for e2x.
Approximate e−0.98 by finding P(0.49) and then using the reciprocal P(0.49)1.
Calculate the absolute and relative errors.
Fifth Maclaurin Polynomial for e2x
The given polynomial form is:
P(x)=(((x+3)x+)x+2)x+2)x+1
This appears to be incorrectly formatted, but we'll write out the correct fifth Maclaurin polynomial for e2x:
P5(x)=1+2x+2x2+68x3+2416x4+12032x5P5(x)=1+2x+2x2+34x3+32x4+154x5
Calculating each term:
1+2(0.49)=0.98+2(0.49)2=2(0.2401)=0.4802+34(0.49)3=34(0.117649)=30.470596=0.156865+32(0.49)4=32(0.05764801)=30.11529602=0.038432+154(0.49)5=154(0.028236441)=150.112945764=0.007530
Summing these terms:
P5(0.49)=1+0.98+0.4802+0.156865+0.038432+0.007530P5(0.49)≈2.6630