Math Problem Statement

Tolong jawab

A real-estate firm owns the Parklane Garden Apartments, which consist of 96 apartments. At $550 per month, every apartment can be rented. However, for each $25 per month increase, there will be three vacancies with no possibility of filling them. The firm wants to receive $54,600 per month from rent. What rent should be charged for each apartment?

Solution

To solve this problem, let's break it down step-by-step:

Problem Statement

  • Total Apartments: 96
  • Current Rent per Apartment: $550 per month
  • Current Occupancy: 96 apartments are fully occupied.
  • Income Goal: $54,600 per month.
  • Vacancy Condition: For every $25 increase in rent, 3 apartments will become vacant.

Goal

We need to find the rent per apartment that will result in the total monthly income of $54,600.

Step-by-Step Solution

  1. Define Variables:

    • Let the number of $25 increments be xx.
    • New rent per apartment: 550+25x550 + 25x.
    • Number of rented apartments after xx increments: 963x96 - 3x.
  2. Total Income Formula: Total Income = (Number of rented apartments) × (New rent per apartment)

    So, the total income is: (963x)×(550+25x)(96 - 3x) \times (550 + 25x)

  3. Set up the Equation: To meet the monthly income goal of $54,600, set up the equation: (963x)(550+25x)=54,600(96 - 3x)(550 + 25x) = 54,600

  4. Expand the Equation: Expanding the left side: 96×550+96×25x3x×5503x×25x=54,60096 \times 550 + 96 \times 25x - 3x \times 550 - 3x \times 25x = 54,600 52,800+2,400x1,650x75x2=54,60052,800 + 2,400x - 1,650x - 75x^2 = 54,600 Simplify: 52,800+750x75x2=54,60052,800 + 750x - 75x^2 = 54,600 75x2+750x+52,800=54,600-75x^2 + 750x + 52,800 = 54,600 75x2+750x1,800=0-75x^2 + 750x - 1,800 = 0 Divide through by -75: x210x+24=0x^2 - 10x + 24 = 0

  5. Solve the Quadratic Equation: x210x+24=0x^2 - 10x + 24 = 0 Using the quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where a=1a = 1, b=10b = -10, and c=24c = 24: x=10±(10)24×1×242×1x = \frac{10 \pm \sqrt{(-10)^2 - 4 \times 1 \times 24}}{2 \times 1} x=10±100962x = \frac{10 \pm \sqrt{100 - 96}}{2} x=10±22x = \frac{10 \pm 2}{2} x=122=6orx=82=4x = \frac{12}{2} = 6 \quad \text{or} \quad x = \frac{8}{2} = 4

  6. Calculate Rent for Each Scenario:

    • If x=4x = 4: Rent = 550+25×4=650550 + 25 \times 4 = 650.
    • If x=6x = 6: Rent = 550+25×6=700550 + 25 \times 6 = 700.
  7. Check Income for Each Rent:

    • For x=4x = 4:

      • Occupied apartments = 963×4=8496 - 3 \times 4 = 84.
      • Income = 84×650=54,60084 \times 650 = 54,600.
      • This matches the goal.
    • For x=6x = 6:

      • Occupied apartments = 963×6=7896 - 3 \times 6 = 78.
      • Income = 78×700=54,60078 \times 700 = 54,600.
      • This also matches the goal.

Conclusion

The rent could be either:

  1. $650 per month (with 84 apartments occupied), or
  2. $700 per month (with 78 apartments occupied).

Do you have any questions, or would you like more details?

Related Questions:

  1. How would the solution change if each $50 increase caused 6 vacancies?
  2. What would happen to the rent if the company wanted to achieve an income of $60,000 per month?
  3. How many total vacancies would there be at a rent of $675 per apartment?
  4. How do changes in vacancy rates impact the overall profit?
  5. How can we calculate the rent if the company wants no more than 5 vacancies?

Tip:

Always check multiple solutions for quadratic equations, as both may be valid for different conditions.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Revenue Maximization

Formulas

Revenue = (Number of Rented Apartments) × (Rent per Apartment)
Quadratic equation formula: ax^2 + bx + c = 0

Theorems

Quadratic formula

Suitable Grade Level

Grades 9-12