Math Problem Statement

Find the antiderivative for each function when C equals 0. Do as many as you can mentally. Check your answers by differentiation. a. 5x^4 b. x^11 c. x^2 - 8x + 15

Solution

Let's find the antiderivatives for each function given, assuming C=0C = 0. This means we’ll ignore the constant of integration.

The power rule for antiderivatives states that if f(x)=xnf(x) = x^n, then: xndx=xn+1n+1+C\int x^n \, dx = \frac{x^{n+1}}{n+1} + C when n1n \neq -1.

Solutions:

a. f(x)=5x4f(x) = 5x^4

For 5x45x^4, increase the exponent by 1 and divide by the new exponent: 5x4dx=5x4+14+1=5x55=x5\int 5x^4 \, dx = 5 \cdot \frac{x^{4+1}}{4+1} = 5 \cdot \frac{x^5}{5} = x^5

b. f(x)=x11f(x) = x^{11}

For x11x^{11}, apply the power rule: x11dx=x11+111+1=x1212\int x^{11} \, dx = \frac{x^{11+1}}{11+1} = \frac{x^{12}}{12}

c. f(x)=x28x+15f(x) = x^2 - 8x + 15

We can take the antiderivative term by term:

  1. For x2x^2: x2dx=x2+12+1=x33\int x^2 \, dx = \frac{x^{2+1}}{2+1} = \frac{x^3}{3}
  2. For 8x-8x: 8xdx=8x1+11+1=8x22=4x2\int -8x \, dx = -8 \cdot \frac{x^{1+1}}{1+1} = -8 \cdot \frac{x^2}{2} = -4x^2
  3. For 1515: 15dx=15x\int 15 \, dx = 15x

So, combining these: (x28x+15)dx=x334x2+15x\int \left( x^2 - 8x + 15 \right) dx = \frac{x^3}{3} - 4x^2 + 15x

Summary of Antiderivatives:

  • a. x5x^5
  • b. x1212\frac{x^{12}}{12}
  • c. x334x2+15x\frac{x^3}{3} - 4x^2 + 15x

Would you like me to verify these results by differentiation or provide further details?


Related Questions:

  1. What is the antiderivative of xnx^{n} in general?
  2. How would the answer change if C0C \neq 0?
  3. What is the role of constants in antiderivatives?
  4. How can you verify an antiderivative through differentiation?
  5. How does the power rule change when n=1n = -1?

Tip:

When finding antiderivatives, always add CC unless specifically told not to, as it represents the family of all antiderivatives.

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Math Problem Analysis

Mathematical Concepts

Antiderivatives
Integration
Power Rule

Formulas

∫x^n dx = x^(n+1)/(n+1) + C when n ≠ -1
∫a dx = ax for constant a

Theorems

Power Rule for Integration

Suitable Grade Level

Grades 11-12