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The problem you uploaded is about motion with constant acceleration and involves two questions:

### Given dataThe problem you uploaded is about motion with constant acceleration and involves two questions:

### Given 
- Distance between two points: \( s = 70.0 \, \text{m} \)
- Time taken to cover this distance: \( t = 7.00 \, \text{s} \)
- Speed at the second point: \( v_f = 15.0 \, \text{m/s} \)

### To find:
(a) Speed at the first point, \( v_i \)  
(b) The acceleration, \( a \)

### (a) Finding the initial speed:
We can use the kinematic equation for distance when acceleration is constant:
\[
s = \frac{v_i + v_f}{2} \cdot t
\]
Solving for \( v_i \):
\[
v_i = \frac{2s}{t} - v_f
\]

Substituting the given values:
\[
v_i = \frac{2(70.0)}{7.00} - 15.0
\]
\[
v_i = \frac{140.0}{7.00} - 15.0 = 20.0 - 15.0 = 5.0 \, \text{m/s}
\]

Thus, the speed at the first point is \( 5.0 \, \text{m/s} \).

### (b) Finding the acceleration:
Now, using the following kinematic equation:
\[
v_f = v_i + a \cdot t
\]
Solving for \( a \):
\[
a = \frac{v_f - v_i}{t}
\]

Substituting the known values:
\[
a = \frac{15.0 - 5.0}{7.00} = \frac{10.0}{7.00} \approx 1.43 \, \text{m/s}^2
\]

Thus, the acceleration is approximately \( 1.43 \, \text{m/s}^2 \).

### Summary:
- (a) The speed at the first point is \( 5.0 \, \text{m/s} \).
- (b) The acceleration is approximately \( 1.43 \, \text{m/s}^2 \).

Would you like more details on any step? 

Here are 5 related questions for practice:
1. How would the problem change if the antelope had an initial velocity of 0 m/s?
2. How can you find the total distance traveled if acceleration was negative?
3. If the time taken to cover the distance was doubled, what would happen to the final velocity?
4. Can you calculate the average velocity between the two points using the data provided?
5. How would you find the displacement after a different time period with the same acceleration?

**Tip:** Always check units for consistency when working through kinematic equations to avoid calculation errors.

An antelope moving with constant acceleration covers the distance between two points 70.0 m apart in 7.00 s. Its speed as it passes the second point is 15.0 m/s. (a) What is its speed at the first point? (b) What is its acceleration?

Solve for the initial speed and acceleration of an antelope moving with constant acceleration over 70.0 m in 7.00 s. This problem involves key kinematic equations for constant acceleration and provides step-by-step calculations. Suitable for high school physics students.

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