To find the time it takes for the deer to reach maximum height, we focus on the vertical component of the deer’s velocity. The formula for the time to reach maximum height in projectile motion is given by:

$t_{\text{max}} = \frac{v_{0y}}{g}$

Where:

• $v_{0y}$ is the initial vertical velocity (the vertical component of the initial velocity),
• $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$).

First, let's find $v_{0y}$, the vertical component of the initial velocity. This can be found using the formula:

$v_{0y} = v_0 \sin \theta$

Where:

• $v_0 = 3.75 \, \text{m/s}$ (the initial velocity),
• $\theta = 46.3^\circ$ (the angle of projection).

Let's calculate $v_{0y}$:

$v_{0y} = 3.75 \sin(46.3^\circ)$

Next, we can calculate $t_{\text{max}}$:

$t_{\text{max}} = \frac{v_{0y}}{9.8}$

Let me calculate this.The time it takes for the deer to reach maximum height is approximately $0.277$ seconds.

Would you like more details or have any further questions?

Here are five related questions to explore:

1. What is the total time the deer spends in the air?
2. What is the maximum height the deer reaches?
3. How far does the deer travel horizontally before landing?
4. What is the horizontal velocity of the deer during its motion?
5. How would the results change if the deer jumps at a different angle?

Tip: In projectile motion, horizontal velocity remains constant, while vertical velocity changes due to gravity.