The test statistic in this case is the F-value for the "Treatment" source of variation. According to the data provided, the F-value is 23.89.

To ensure precision, it is already given and doesn't require further calculation.

The test statistic is:

$F = 23.8900$

Would you like any further details or clarification?

Here are five related questions:

1. How is the F-value calculated in an ANOVA test?
2. What does the p-value in an ANOVA table represent?
3. What are the assumptions behind using ANOVA?
4. How do degrees of freedom (df) affect the F-distribution?
5. What does it mean if the p-value is less than 0.05?

Tip: The F-ratio in an ANOVA is computed by dividing the mean square for the treatment by the mean square for the error.