Math Problem Statement

To test whether the mean time to mix a batch of adhesive is the same for machines produced by four manufacturers, TiteBondMax obtained the uploaded DATA on the time (minutes) needed to mix the materials. Test whether the machines have equal mean mixing time at α = 0.05.

Select one of the following options to answer question above:

The data provide strong evidence against H0: Equal means at pvalue 0.013. The mixing machines are not all equal.

The pvalue 0.0001 is extreme evidence that the machines are not all the same.

The data provide weak evidence against H0: Equal means at pvalue 0.072. Equality of means remains plausible.

The data provide extreme evidence against H0: Equal means at pvalue 0.001. The mixing machines are not all equal.

None of the answers match my calculation.

The data provide insignificant evidence against H0: Equal means at pvalue 0.514. The machine are considered equal.

To test whether the mean time to mix a batch of adhesive is the same for machines produced by four manufacturers, TiteBondMax obtained the uploaded DATA on the time (minutes) needed to mix the materials. Test whether the machines have equal mean mixing time at α = 0.05.

Solution

To answer your question, I will perform an Analysis of Variance (ANOVA) test to determine if the mean mixing times for the machines produced by the four manufacturers are equal, given a significance level of α=0.05\alpha = 0.05. Let me calculate it for you. numpy as np import scipy.stats as stats

Data extracted from the table

manufacturer_A = [25, 23, 21, 23] manufacturer_B = [23, 21, 23, 24] manufacturer_C = [25, 25, 25, 21] manufacturer_D = [22, 23, 23, 22]

Perform one-way ANOVA test

f_statistic, p_value = stats.f_oneway(manufacturer_A, manufacturer_B, manufacturer_C, manufacturer_D)

f_statistic, p_valueThe ANOVA test results are:

  • FF-statistic: 0.806
  • pp-value: 0.514

Since the pp-value (0.5140.514) is greater than the significance level (α=0.05\alpha = 0.05), we fail to reject the null hypothesis (H0H_0). This means there is insufficient evidence to conclude that the mean mixing times for the machines are different. The machines can be considered to have equal mean mixing times.

Correct Answer:

The data provide insignificant evidence against H0H_0: Equal means at pp-value 0.514. The machines are considered equal.


Do you want further explanation on the ANOVA test or its interpretation? Here are 5 related questions for deeper understanding:

  1. What does the FF-statistic represent in ANOVA?
  2. How do we calculate the FF-statistic manually?
  3. What assumptions must be met to perform an ANOVA test?
  4. How would we interpret the result if the pp-value was less than 0.05?
  5. Can ANOVA be used for more than 4 groups, and how does that affect the test?

Tip: Always check the assumptions of ANOVA (e.g., normality and equal variances) before interpreting results for accuracy!

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Math Problem Analysis

Mathematical Concepts

Statistics
Analysis of Variance (ANOVA)

Formulas

F-statistic = Between-group variability / Within-group variability

Theorems

Null Hypothesis (H0): All group means are equal
Alternative Hypothesis (H1): At least one group mean is different

Suitable Grade Level

Undergraduate level (Statistics or Business Analytics)