Math Problem Statement
The cross- section of a piece of conduit is an annulus. It has an outer diameter of 60mm and an inner diameter of 50mm. A- find the area of the cross-section to the nearest square mm. B- what is the increase in cross- section area if the outer diameter is increased 65mm? Answer to nearest square mm.
Solution
Let's go step by step through the problem.
Part A: Find the area of the cross-section of the annulus.
The area of an annulus is given by the formula:
Where:
- is the outer radius,
- is the inner radius.
We are given:
- The outer diameter is 60 mm, so mm.
- The inner diameter is 50 mm, so mm.
Substituting these values into the formula:
Now, let's calculate the area to the nearest square millimeter.
So, the area of the cross-section is approximately 864 mm².
Part B: What is the increase in cross-section area if the outer diameter is increased to 65 mm?
For this, we calculate the new area with the outer diameter of 65 mm and find the difference.
- The new outer radius is mm.
- The inner radius remains mm.
The new area is:
Now, let's calculate the new area:
To find the increase in area, subtract the original area from the new area:
So, the increase in the cross-section area is approximately 491 mm².
Final Answers:
- Part A: The area of the cross-section is approximately 864 mm².
- Part B: The increase in cross-section area is approximately 491 mm².
Would you like more details on any part of this? Here are some related questions to explore:
- How would the area change if the inner diameter also increased?
- What is the significance of the annular shape in conduit design?
- How can we model the volume of such a conduit if the length is known?
- How does the change in radius affect the area growth in general?
- How would you calculate the material cost for the conduit based on cross-sectional area?
Tip: When working with diameters and radii, always remember to halve the diameter to find the radius before applying area formulas!
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Math Problem Analysis
Mathematical Concepts
Geometry
Annulus Area Calculation
Area Difference
Formulas
Area of annulus: A = π(R^2 - r^2)
Outer radius: R = diameter / 2
Inner radius: r = diameter / 2
Theorems
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Suitable Grade Level
Grades 9-12
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