What is the value of the angular velocity of a point on the surface of the Earth?
A 1.2 × 10–5
 rad s–1
B 7.3 × 10–5
 rad s–1
C 2.6 × 10–1
 rad s–1
D 4.6 × 102
 rad s–1

The angular velocity (\( \omega \)) of a point on the surface of the Earth can be calculated using the fact that the Earth rotates once every 24 hours. The formula for angular velocity is:

\[
\omega = \frac{2\pi}{T}
\]

where:
- \( T \) is the period of rotation, which is the time it takes for the Earth to make one full rotation (24 hours or 86400 seconds).

Substituting \( T = 86400 \) seconds:

\[
\omega = \frac{2\pi}{86400} \approx 7.27 \times 10^{-5} \text{ rad/s}
\]

So, the closest answer is:

**B. \( 7.3 \times 10^{-5} \text{ rad/s} \)**

### Would you like more details or have any questions?

Here are 5 related questions for deeper exploration:
1. How does the angular velocity of the Earth vary with latitude?
2. How can you calculate the linear velocity of a point on Earth's equator?
3. What is the difference between angular velocity and linear velocity?
4. How would the angular velocity change if the Earth rotated faster?
5. What is the angular velocity of a satellite orbiting the Earth?

**Tip:** To convert between angular velocity and linear velocity, use the formula \( v = \omega r \), where \( r \) is the radius.

What is the value of the angular velocity of a point on the surface of the Earth?

Find the angular velocity of a point on the Earth's surface using the formula ω = 2π / T, where T is Earth's rotation period of 24 hours. This physics problem involves circular motion and angular velocity concepts, making it suitable for Grades 10-12.

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